This check is responsible for using the auto type specifier for variable declarations to improve code readability and maintainability. For example:

std::vector<int>::iterator I = my_container.begin();

// transforms to:

auto I = my_container.begin();

The auto type specifier will only be introduced in situations where the variable type matches the type of the initializer expression. In other words auto should deduce the same type that was originally spelled in the source. However, not every situation should be transformed:

int val = 42;
InfoStruct &I = SomeObject.getInfo();

// Should not become:

auto val = 42;
auto &I = SomeObject.getInfo();

In this example using auto for builtins doesn’t improve readability. In other situations it makes the code less self-documenting impairing readability and maintainability. As a result, auto is used only introduced in specific situations described below.


Iterator type specifiers tend to be long and used frequently, especially in loop constructs. Since the functions generating iterators have a common format, the type specifier can be replaced without obscuring the meaning of code while improving readability and maintainability.

for (std::vector<int>::iterator I = my_container.begin(),
                                E = my_container.end();
     I != E; ++I) {

// becomes

for (auto I = my_container.begin(), E = my_container.end(); I != E; ++I) {

The check will only replace iterator type-specifiers when all of the following conditions are satisfied:

  • The iterator is for one of the standard container in std namespace:
    • array
    • deque
    • forward_list
    • list
    • vector
    • map
    • multimap
    • set
    • multiset
    • unordered_map
    • unordered_multimap
    • unordered_set
    • unordered_multiset
    • queue
    • priority_queue
    • stack
  • The iterator is one of the possible iterator types for standard containers:
    • iterator
    • reverse_iterator
    • const_iterator
    • const_reverse_iterator
  • In addition to using iterator types directly, typedefs or other ways of referring to those types are also allowed. However, implementation-specific types for which a type like std::vector<int>::iterator is itself a typedef will not be transformed. Consider the following examples:
// The following direct uses of iterator types will be transformed.
std::vector<int>::iterator I = MyVec.begin();
  using namespace std;
  list<int>::iterator I = MyList.begin();

// The type specifier for J would transform to auto since it's a typedef
// to a standard iterator type.
typedef std::map<int, std::string>::const_iterator map_iterator;
map_iterator J = MyMap.begin();

// The following implementation-specific iterator type for which
// std::vector<int>::iterator could be a typedef would not be transformed.
__gnu_cxx::__normal_iterator<int*, std::vector> K = MyVec.begin();
  • The initializer for the variable being declared is not a braced initializer list. Otherwise, use of auto would cause the type of the variable to be deduced as std::initializer_list.

New expressions

Frequently, when a pointer is declared and initialized with new, the pointee type has to be written twice: in the declaration type and in the new expression. In this cases, the declaration type can be replaced with auto improving readability and maintainability.

TypeName *my_pointer = new TypeName(my_param);

// becomes

auto *my_pointer = new TypeName(my_param);

The check will also replace the declaration type in multiple declarations, if the following conditions are satisfied:

  • All declared variables have the same type (i.e. all of them are pointers to the same type).
  • All declared variables are initialized with a new expression.
  • The types of all the new expressions are the same than the pointee of the declaration type.
TypeName *my_first_pointer = new TypeName, *my_second_pointer = new TypeName;

// becomes

auto *my_first_pointer = new TypeName, *my_second_pointer = new TypeName;

Known Limitations

  • If the initializer is an explicit conversion constructor, the check will not replace the type specifier even though it would be safe to do so.
  • User-defined iterators are not handled at this time.



If the option is set to non-zero (default is 0), the check will remove stars from the non-typedef pointer types when replacing type names with auto. Otherwise, the check will leave stars. For example:

TypeName *my_first_pointer = new TypeName, *my_second_pointer = new TypeName;

// RemoveStars = 0

auto *my_first_pointer = new TypeName, *my_second_pointer = new TypeName;

// RemoveStars = 1

auto my_first_pointer = new TypeName, my_second_pointer = new TypeName;